Question

2(3х+1)-х<3(х+4);
2(х-1)-3(х+2)<6(1+х);
7х+4(х-2)>6(1+3)х;
7(y+3)-2(y+2)>(5y+1)
​

Answer 1

Ответ:

5x+2<3х+12 => 2x<10 => x<5;

-x-8<6+х => -14<7x => -2< x;

11x-8 >24х => -8 >13x => -8/13 > x;

7(y+3)-2(y+2)>(5y+1) => 5y+17 > 5y+1 => 0y>-16 =>

Пошаговое объяснение: