Question

70, 71 алгебрп, 8 клас​

Answer 1

Ответ:

70.

1)

$0,2\sqrt{400} -\frac{1}{3} \sqrt{81} =0.2*20-\frac{1}{3}*9= 4-3=1$

2)

$\sqrt{49} *\sqrt{0.09}+\sqrt{2^3+1}=7\sqrt{\frac{9}{100} } +\sqrt{8+1}=7*\frac{3}{10} +\sqrt{9} =\frac{21}{10} +3 = 5,1$

3)

$5\sqrt{0.64}-\sqrt{5^2+12^2}=5\sqrt{\frac{16}{25} } -\sqrt{25+144} =5*\frac{4}{5}-\sqrt{169} = 4 - 13 = -9$

71.

1)

$\sqrt{6} ^2-\sqrt{0.81} = 6 - \sqrt{\frac{81}{100} } = 6-\frac{9}{10} =5.1$

2)

$(2\sqrt{7} )^2-(7\sqrt{2} )^2 = 4*7-49*2=28-98=-70$

3)

$18*(-\frac{1}{3}*\sqrt{5})^2-\frac{1}{6}*(4\sqrt{3})^2=18*\frac{1}{9}*5-\frac{1}{2}*16=2*5-8=10-8=2$

4)

$\sqrt{961} - (\frac{1}{5} * \sqrt{125})^2 = 31 - 5 = 26$