Question

Помогите решить уравнение

Answer 1

$tg\frac{x}{2}=\frac{\sqrt{3} }{3}\\\\\frac{x}{2}=arctg\frac{\sqrt{3} }{3} +\pi n,n\in Z\\\\\frac{x}{2}=\frac{\pi }{6}+\pi n,n\in Z\\\\\boxed{x=\frac{\pi }{3}+2\pi n,n\in Z }$