Question

39.5 ʕ´•ᴥ•`ʔпомогите )​

Answer 1

Ответ:

2) $\frac{2}{x}$ 4)$\frac{4}{7}$ 6)1 2)$-\frac{10}{107}$ 4)2

Объяснение:

39.5

2)$\frac{2x-3y+11y-2x}{4xy}$

$\frac{-3y+11y}{4xy}$

$\frac{8y}{4xy}$

$\frac{2}{x}$

4)$\frac{a-2+2a+5-(3-a)}{7a}$

$\frac{a-2+2a+5-3+a}{7a}$

$\frac{4a+0}{7a}$

$\frac{4a}{7a}$

$\frac{4}{7}$

6)$\frac{21a+2b}{6a} +\frac{3(7a-b)}{6a} -\frac{36a-b}{6a}$

$\frac{21a+2b}{6a} +\frac{7a-b}{2a} -\frac{36a-b}{6a}$

$\frac{21a+2b+3(7a-b)-(36a-b)}{6a}$

$\frac{21a+2b+21a-3b-36a+b}{6a}$

$\frac{6a+2b-3b+b}{6a}$

$\frac{6a+0}{6a}$

$\frac{6a}{6a}$

1

39.6

2)$\frac{12,7}{(\frac{57}{10}) ^{2}-25 } -\frac{11,4+2}{(\frac{57}{10}) ^{2}-25 }$

$\frac{\frac{127}{10} }{(\frac{57}{10})^{2}-25} - \frac{13,4}{(\frac{57}{10})^{2}-25}$

$\frac{127}{10((\frac{57}{10})^{2}-25)} -\frac{\frac{67}{5} }{(\frac{57}{10})^{2}-25}$

$\frac{127}{10(\frac{3249}{100}-25)}-\frac{67}{5((\frac{57}{10})^{2}-25)}$

$\frac{127}{10*\frac{749}{100}} - \frac{67}{5(\frac{3249}{100}-25)}$

$\frac{127}{\frac{749}{10}} - \frac{67}{5*\frac{749}{100}}$

$\frac{1270}{749} - \frac{67}{\frac{749}{20} }$

$\frac{1270}{749} - \frac{1340}{749}$

$-\frac{10}{107}$

4)$\frac{40,5-1}{(\frac{9}{2})^{2} -9} -\frac{27-10}{(\frac{9}{2})^{2}-9 }$

$\frac{39,5}{\frac{81}{4}-9} - \frac{17}{\frac{81}{4}-9}$

$\frac{\frac{79}{2} }{\frac{45}{4}} - \frac{17}{\frac{45}{4} }$

$\frac{158}{45}-\frac{68}{45}$

2

Answer 2

Ответ:

вот кеш жібергенм үшн ренжме)

Объяснение:

бұны мен жазбадым но дұрыс)