Question

помогите с этим заданием​

Answer 1

Ответ:

$1)7 \frac{9}{16} \div \frac{33}{80} = \frac{121}{16} \times \frac{80}{33} = \frac{11 \times 5}{3} = \frac{55}{3} = 18 \frac{1}{3} \\ 2)18 \frac{1}{3} - 21 \frac{5}{6} = 18 \frac{2}{6} - 21 \frac{5}{6} = - 3 \frac{3}{6} = - 3 \frac{1}{2}$

$3)51 \frac{4}{9} - 49 \frac{75}{100 } = 51 \frac{4}{9} - 49 \frac{3}{4} = 51 \frac{16}{36} - 49 \frac{27}{36} = 50 \frac{52}{36} - 49 \frac{27}{36} = 1 \frac{25}{36}$

$4)1 \frac{25}{36} \div 8 \frac{17}{36} = \frac{61}{36} \div \frac{305}{36} = \frac{61}{36} \times \frac{36}{305} = \frac{61}{305} = 0.2 \\ 5)0.2 + 6.8 = 7 \\ 6) - 3 \frac{1}{2} \div 7 = - \frac{7}{2} \div 7 = - \frac{7}{2} \times \frac{1}{7} = - \frac{1}{2} = - 0.5$

ответ: -0.5