Question

$(3x+1) ^{2}=(3x-10) ^{2}$

Answer 1

$(3x+1) ^2=(3x-10) \ 9X+6x+1=9x^2-60x+100 \ 66x=99 \ 2x=3 \ D=b^2-4ac \ D=4356=66^2 \ x=3/2$