Question

(2x-3)²-3(x-2)(x+2)=(x-2)(x+1)+1
пожалуйста!!! помогите!!!​

Answer 1

$(2x-3)^{2} -3(x-2)(x+2)=(x-2)(x+1)+1$

$4x^{2}-12x+9-3(x^{2}-4)=x^{2}+x-2x-2+1$

$4x^{2}-12x+9-3x^{2}+12=x^{2}-x-1$

$x^{2}-12x+21=x^{2}-x-1$

$-12x+21=-x-1$

$-12x+x=-1-21$

$-11x=-22$

$x=2$

Answer 2

$(2x-3)^{2}-3(x-2)(x+2)=(x-2)(x+1)+1\\\\4x^{2}-12x+9-3(x^{2} -4)=x^{2}+x-2x-2+1\\\\4x^{2}-12x+9-3x^{2}+12=x^{2} -x-1\\\\x^{2}-12x-x^{2}+x=-1-21\\\\-11x=-22\\\\x=-22:(-11)=2\\\\Otvet:\boxed{2}$