Question

срочно !!!!! допоможіть

Answer 1

$\displaystyle1.\ \sqrt{(-\sqrt3)^2+\sqrt{(-13)^2}}=\sqrt{(-\sqrt3)^2+13}}=\\\\=\sqrt{3+13}=\sqrt{16}=\boxed{4}\\\\\\\displaystyle2.\ \sqrt{2^8}-(\sqrt{3})^6+\sqrt{4^3}=\sqrt{{\big(2^4\big)}^2}-\big({(\sqrt3)^2\big)}^3+(\sqrt4)^3=\\\\=2^4-3^3+2^3=16-27+8=\boxed{-3}\\\\\\\displaystyle3.\ \sqrt{\sqrt{125}\cdot\sqrt{32}\cdot\sqrt{2,5}}=\sqrt{\sqrt{125\cdot32\cdot2,5}}=\sqrt{\sqrt{10000}}=\sqrt{100}=\boxed{10}$