Question

$\sqrt{b-2\sqrt{b+7} + 8 } + \sqrt{b+2\sqrt{b+7} + 8 }$

Answer 1

Ответ:

Пошаговое объяснение:

$\sqrt{b-2\sqrt{b+7}+8}+\sqrt{b+2\sqrt{b+7}+8}\\\sqrt{b+7-2\sqrt{b+7}+1}+\sqrt{b+7+2\sqrt{b+7}+1}\\\sqrt{(\sqrt{b+7}-1)^2}+\sqrt{(\sqrt{b+7}+1)^2}\\|\sqrt{b+7}-1|+|\sqrt{b+7}+1|\\if \ b\geqslant-6, \ then \ 2\sqrt{b+7}\\if \ b \in[-7; -6), \ then \ 2$