Question

Помогите пожалуйста решить!!!​

Answer 1

$10\dfrac{9}{16} -(3\dfrac{11}{12} +4\dfrac{4}{9} )=2\dfrac{29}{144}$

1) $3\dfrac{11}{12} +4\dfrac{4}{9}=3\dfrac{33}{36} +4\dfrac{16}{36}=7\dfrac{49}{36} =8\dfrac{13}{36}$

2) $10\dfrac{9}{16} - 8\dfrac{13}{36} =10\dfrac{81}{144} - 8\dfrac{52}{144} =2\dfrac{29}{144}$

Answer 2

Ответ:

$2\frac{29}{144}$

Пошаговое объяснение:

$10\frac{9}{16}-(3\frac{11}{12}+4\frac{4}{9})=10\frac{9*9}{16*9}-(3\frac{11*12}{12*12}+4\frac{4*16}{9*16})=10\frac{81}{144}-(3\frac{132}{144}+4\frac{64}{144})=10\frac{81}{144}-7\frac{196}{144}=10\frac{81}{144}-8\frac{52}{144}=2\frac{29}{144}$