Question

помогите по алгебре.
Есть ещё вторая часть.​

Answer 1

Объяснение:

1)

$- 0.4x {}^{2} y \times ( - 10xy {)}^{2} = 4x {}^{3} y {}^{3}$

3)

$(0.25x {}^{ - 2} y {}^{ - 1} ) {}^{ - 3} = ( \frac{1}{4} \times \frac{1}{x {}^{2} } \times \frac{1}{y} ) {}^{ - 3} = ( \frac{1}{4x {}^{2} y} ) {}^{ - 3} = (4x {}^{2} y) {}^{3} = 64x {}^{6} y {}^{3}$

5)

$ab( - 5ab {}^{2} ) \times (4a {}^{2} b) = - ab \times 5ab {}^{2} \times 4a {}^{2} b = - 20a {}^{4} b {}^{4}$