Question

Срочно отдам все балы​

Answer 1

Объяснение:

решение на данном фото

Answer 2

$(\frac{64y}{y^2-64} +\frac{4y}{y+8} -\frac{5y}{32-4y} ):\frac{3y}{4y-32} =7$

$(\frac{64y}{(y-8)(y+8)} +\frac{4y}{y+8} +\frac{5y}{4(y-8)} ):\frac{3y}{4y-32} =7$

$(\frac{64y*4+4y(y-8)*4+5y(y+8)}{4(y-8)(y+8)} ):\frac{3y}{4y-32} =7$

$\frac{256y+16y^2-128y+5y^2+40y}{4(y-8)(y+8)} :\frac{3y}{4y-32} =7$

$\frac{21y^2+168y}{4(y-8)(y+8)} :\frac{3y}{4y-32} =7$

$\frac{21y(y+8)}{4(y-8)(y+8)} :\frac{3y}{4y-32} =7$

$\frac{21y}{4(y-8)} *\frac{4y-32}{3y} =7$

$\frac{21y}{4(y-8)} *\frac{4(y-8)}{3y} =7$

$\frac{21y*4*(y-8)}{4(y-8)*3y} =7$

$\frac{7}{1} =7$

$7=7$