Question

Допоможіть пж пж пж




Птьаататв

Answer 1

Номер ✓1

$\frac{14}{x {}^{2} } \times \frac{x}{7} = \frac{2}{x}$

Номер ✓2

$\frac{b}{9} \div \frac{b}{8} = \frac{b}{9} \times \frac{8}{b} = \frac{1}{8} \times 8 = \frac{8}{9}$

Номер ✓3

$1)( - \frac{2x {}^{3} }{a {}^{4} } ) {}^{3} = - ( \frac{2x {}^{2} }{a {}^{4} }) {}^{3} = - \frac{(2x {}^{2}) {}^{3} }{(a {}^{4}) {}^{3} } = - \frac{8x {}^{6} }{a {}^{12} }$

$2)( \frac{ab {}^{4} }{c {}^{5} } ) {}^{6} = \frac{(ab {}^{4}) {}^{6} }{(c {}^{5}) {}^{6} } = \frac{a {}^{6} b {}^{24} }{c {}^{30} }$

Номер ✓4

$1) \frac{4n {}^{3} }{25k {}^{2} } \times ( - \frac{5k}{16n {}^{3} } ) = - \frac{1}{5k} \times \frac{1}{4} = - \frac{1}{20k}$

$2) \frac{16 - a {}^{2} }{8 - 4a} \div \frac{12 - 3a}{10 - 5a} = \frac{(4 - a) \times (4 + a)}{4(2 - a)} \times \frac{10 - 5a}{12 - 3a} = \frac{(4 - a) \times (4 + a)}{4(2 - a)} \times \frac{5(2 - a)}{3(4 - a)} = \frac{4 + a}{4} \times \frac{5}{3} = \frac{5(4 + a)}{12} = \frac{20 + 5a}{12}$