Question

Помогите срочно !!!!!​

Answer 1

Ответ:

1) $x^2$

2) $a^2$

3) $b*(5a+1,9b)$

4) $2y*(x-1,1y)$

Объяснение:

1) $\frac{1}{3}x^2-\frac{1}{3}y+\frac{2}{3}x^2+\frac{1}{3}y=(\frac{1}{3}x^2+\frac{2}{3}x^2)-(\frac{1}{3}y-\frac{1}{3}y)=x^2*(\frac{1}{3}+\frac{2}{3})-0=x^2*1=x^2$

2) $\frac{1}{5}a^2+\frac{3}{4}b^2+\frac{4}{5}a^2-\frac{3}{4}b^2=(\frac{1}{5}a^2+\frac{4}{5}a^2)+(\frac{3}{4}b^2-\frac{3}{4}b^2)=a^2*(\frac{1}{5}+\frac{4}{5})+0=a^2*1=a^2$

3) $2ab+0,7b^2-5ab+1,2b^2+8ab=(2ab-5ab+8ab)+(0,7b^2+1,2b^2)=5ab+1,9b^2=b*(5a+1,9b)$

4) $5xy-3,5y^2-2xy+1,3y^2-xy=(5xy-2xy-xy)-(3,5y^2-1,3y^2)=2xy-2,2y^2=2y*(x-1,1y)$