Question

спростіть вираз (y-8) (2y-1)+(3y+1)(5y-2)​

Answer 1

Пошаговое объяснение:

$(y - 8)(2y - 1) + (3y + 1)(5y - 2) = 2y^{2}-y-16y+8+\left(3y+1\right)\left(5y-2\right) =2y^{2}-17y+8+\left(3y+1\right)\left(5y-2\right) =2y^{2}-17y+8+15y^{2}-6y+5y-2 =2y^{2}-17y+8+15y^{2}-y-2 =17y^{2}-17y+8-y-2 =17y^{2}-18y+8-2 =17y^{2}-18y+6$

Answer 2

Ответ:

$(y - 8)(2y - 1) + (3y + 1)(5y - 2) = 2y {}^{2} - y - 16y + 8 + 15y {}^{2} - 6y + 5y - 2 = 17y {}^{2} - 18y + 6$