Question

Помогите пожалуйста!!
1) -34x²+19=0
2)3x²-20x=0
3) -7x²-x+8=0

Answer 1

Ответ:

$1)x {}^{2} = \frac{19}{24} \\ x = \frac{ \sqrt{646} }{34} \\x = - \frac{ \sqrt{646} }{34} \\ 2)x(3x - 20) = 0 \\ x = 0 \\ x = \frac{20}{3} = 6 \times \frac{2}{3} \\ 3)7x {}^{2} + x - 8 = 0 \\ (7x + 8)(x - 1) = 0 \\ x = - \frac{8}{7} \\ x = 1$