Question

3 номер помогите срочно ​

Answer 1

$\displaystyle\bf\\1) \ \ 6\sqrt{\frac{2}{3} } =\sqrt{6^{2} \cdot\frac{2}{3} } =\sqrt{36\cdot\frac{2}{3} } =\sqrt{12\cdot 2}=\sqrt{24} \\\\\\2) \ \ \frac{1}{2} \sqrt{88} =\sqrt{\Big(\frac{1}{2}\Big)^{2} \cdot88 } =\sqrt{\frac{1}{4} \cdot88}=\sqrt{22} \\\\\\\sqrt{24} >\sqrt{22} \ \ \ \Rightarrow \ \ \boxed{6\sqrt{\frac{2}{3} } >\frac{1}{2} \sqrt{88} }$

Answer 2

3. 6√(2/3)=√(36*2/3)=√24; (1/2)√88=√(88/4)√22; т.к. 24>22, то √24>√22⇒= 6√(2/3)>(1/2)√88

4. 2√18+5√50-(1/4)√32-7√2=2*3√2+5*5√2-(1/4)*4√2-7√2=

(6+25-1-7)√2=23√2