Question

БЕЗ ИНТЕРНЕТА, ПОЖАЛУЙСТА, ТАМ НЕ ВЕРНО!
даю 50 баллов​

Answer 1

$\displaystyle 1)(x-12)(x+12)=2(6-x)^2-x^2\\x^2-144=2(36-12x+x^2)-x^2\\x^2-144=72-24x+2x^2-x^2\\x^2-144=72-24x+x^2\\-144=72-24x\\24x=72+144\\24x=126\\x=9\\\\2)(2x-5)^2=40+(2x+5)^2\\4x^2-20x+25=40+4x^2+20x+25\\-20x=40+20x\\-20x-20x=40\\-40x=40\\x=-1$

Answer 2

Ответ:

a) x=9

b) x=-1

Объяснение:

a)

$(x-12)(x+12)=2(6-x)^{2}-x^{2}\\x^{2} +12x-12x-144=2(36-12x+x^{2} )-x^{2} \\x^{2} -144=72-24x+2x^{2} -x^{2} \\\\x^{2} -144=72-24x+x^{2}\\x^{2} -x^{2} +24x=144+72\\24x=216\\\\x=216:24\\\\x=9$

b)

$(2x-5)^{2}=40+(2x+5)^{2}\\4x^{2} -20x+25=40+4x^{2} +20x+25\\4x^{2} -20x+25=65+4x^{2} +20x\\4x^{2} -20x+25-4x^{2} -20x=65\\-40x+25=65\\-40x=65-25\\-40x=40\\x=40:(-40)\\x=-1$