Question

(x^2-7*x+10)/(25-x^2)<=0

Answer 1

(x² -7*x + 10)/(25-x²)<=0

(x² -7x + 10)/(x² - 25)≥0

Метод интервалов

(x - 2)(x - 5) / (x - 5)(x + 5) ≥ 0

++++++++(-5) -------------- [2] ++++++ (5) ++++++++++

x ∈ (-∞, -5) U [2,5) U (5, + ∞)