Question

разложите на множители

Answer 1

4) x⁵-3x³+4x²-12=x³(x²-3)+4(x²-3)=(x²+4)(x²-3)

6)ax²+ay-bx²-by+cx²+cy=x²(a-b+c)+y(a-b+c)=(x²+y)(a-b+c)

7) x³-x²+x²y+x-xy+y=x(x²-x+1)+y(x²-x+1)=(x+y)(x²-x+1)

5)20a³bc-28ac²+15a²b²-21bc=5a²b(ac+3b)-7c(4ac+3b)=(5a²b-7c)(ac+3b)