Question

помогите, пожалуйста, с геометрией ಠ﹏ಠ​

Answer 1

Ответ:

ПО теореме Пифагора

$AC^2=AB^2+BC^2 = 64+36 =100\\AC = 10\\sinA = \frac{BC}{AC} = \frac{6}{10} =0.6\\cosA = \frac{AB}{AC} = \frac{8}{10} = 0.8\\ tgA = \frac{BC}{AB} = \frac{6}{8} = 0.75\\ ctgA = \frac{AB}{BC} = \frac{8}{6} = \frac{4}{3} = 1\frac{1}{3} \\ sinC = \frac{AB}{AC} = \frac{8}{10} = 0.8 \\cosC = \frac{BC}{AC} = \frac{6}{10} =0.6\\tgC = \frac{AB}{BC} = \frac{8}{6} = \frac{4}{3} = 1\frac{1}{3} \\ctgC = \frac{BC}{AB} = \frac{6}{8} = 0.75$

Answer 2

Ответ:

решение смотри на фотографии