Question

1.Розв'яжіть систему способом підстановки:
$x = y - 3 \\ 2y - x = 6$
помогите срочно​

Answer 1

Ответ:

(х; у) (0; 3)

Объяснение:

х=у-3           х=у-3          х=0

2у-(у-3)=6   2у-у+3=6    у=3

Answer 2

$\displaystyle\bf\\\left \{ {{x=y-3} \atop {2y-x=6}} \right. \\\\\\\left \{ {{x=y-3} \atop {2y-(y-3)=6}} \right. \\\\\\\left \{ {{x=y-3} \atop {2y-y+3=6}} \right. \\\\\\\left \{ {{x=y-3} \atop {y=3}} \right. \\\\\\\left \{ {{x=3-3} \atop {y=3}} \right. \\\\\\\left \{ {{x=0} \atop {y=3}} \right. \\\\\\Otvet: \ (0 \ ; \ 3)$