Question

Привет.
помогите, пожалуйста решить задание.​

Answer 1

Ответ:

$1) \sqrt{2} * \sqrt{32}=\sqrt{2*32} = \sqrt{64} =8$

$2)\sqrt{10} *\sqrt{90} =\sqrt{10*90} = \sqrt{900} = 30$

$3)\sqrt{3}* \sqrt{7} *\sqrt{21} =\sqrt{3*7*21} =\sqrt{21*21} =\sqrt{21^{2} } =21$

$4) \sqrt{2} *\sqrt{22} *\sqrt{11} =\sqrt{2*22*11} =\sqrt{22*22} =\sqrt{22^{2} } =22$

====

$1)\sqrt{5^{4}*3^{2} } =\sqrt{5^{4} } *\sqrt{3^{2} } =5^{2} *3=25*3=75$

$2)\sqrt{7^{4} *2^{6} } =\sqrt{7^{4} } *\sqrt{2^{6} } = 7^{2} *\sqrt{64} =7^{2} *8=49*8=392$

$3)\sqrt{12^{2}*3^{4} } }= \sqrt{12^{2} } *\sqrt{3^{4}}= 12 *3^{2} =12*9=108$

$4)\sqrt{8^{2}*5^{4} } =\sqrt{8^{2} } *\sqrt{5^{4} } =8*5^{2} =8*25=200$