Question

можете решить пожалуйста даю 20 баллов

Answer 1

$\displaystyle\bf\\\frac{2x^{2} -3}{x-2} -\frac{4x-3}{x-2} =0\\\\\\\frac{2x^{2} -3-4x+3}{x-2} =0\\\\\\\frac{2x^{2} -4x}{x-2} =0\\\\\\\frac{2x(x-2)}{x-2} =0\\\\\\\left \{ {{x=0} \atop {x-2\neq 0}} \right. \\\\\\\left \{ {{x=0} \atop {x\neq 2}} \right. \\\\\\Otvet: \ 0$