Question

Даю 100 балов 7 клас алгебра

Answer 1

$\displaystyle \left \{ {{\frac{2x-1}{10}=2-\frac{9(y-3)}{20} } \atop {\frac{y-4}{4}=\frac{2x-9}{3}-\frac{3}{4} }} \right.\\ \\\left \{ {{x=\frac{69}{4}-\frac{9}{4}y } \atop {\frac{y-4}{4}=\frac{2x-9}{3}-\frac{3}{4} }} \right.\\ \\\frac{y-4}{4}=\frac{2(\frac{69}{4}-\frac{9}{4}y)-9 }{3}-\frac{3}{4}\\ \\y=5\\ \\\frac{5-4}{4}=\frac{2x-9}{3}-\frac{3}{4}\\ \\x=6\\ (x,y)=(6,5)$

Answer 2

Ответ:

х=69\4-9\4 y

y-4\4=2x-9\3-3\4

y-4\4=2(69\4-9\4y)-9\3-3\4

y=5

5-4\4=2x-9\3-3\4

x=6

(x,4)=(6,5)

{2*6-\10=2-9(5-3)\20

{5-4\4=2*6-9\3-3\4

{1\10=11\10

{1\4=1\4

(x,y)=(6,5)

Объяснение:

Думаю понятно написано