Question

10. 1) 4(a - 1)² + (a − 2)(6 - a) - 13; L 2) 5(a 4)² (a - 4)(7 - 2a) + 20a²; 3) (a 5)² + (3a - 2)(7a) - 18a + 6; 4)-(4- 2a)²-(3a - 2)(6 - a) + a². - .2.
пжжж​

Answer 1

$10.$

$1) \: \: \: \: \: 4 {(a - 1)}^{2} + (a - 2)(6 - a) - 13 = 4( {a}^{2} - 2a + 1) + 6a - {a}^{2} - 12 + 2a - 13 = {4a}^{2} - 8a + 4 + 8a - {a}^{2} - 25 = {3a}^{2} - 21 = 3( {a}^{2} - 7) =$

$2) \: \: \: \: \: {(a + 4)}^{2} + (a - 4)(7 - 2a) + {20a}^{2} = {a}^{2} + 8a + 8 + 7a - {2a}^{2} - 28 + 8a + {20a}^{2} = {19a}^{2} + 23a - 20$

$3) \: \: \: \: \: {(a + 5)}^{2} + (3a - 2)(7a) - 18a + 6 = {a}^{2} + 10a + 25 + {21a}^{2} - 14a - 18a + 6 = {22a}^{2} - 22a + 31$

$4) \: \: \: \: \: - (4 - 2a) {}^{2} - (3a - 2)(6 - a) + {a}^{2} - 2 = - (16 - 16a + {4a}^{2} )- 18a + {3a}^{2} + 12 - 2a + {a}^{2} - 2 = - 16 + 16a - {4a}^{2} - 20a + 4 {a}^{2} + 10 = - 4a - 6 = - 2(2a + 3)$