Question

Помогите!!! Даю 50 балов

Answer 1

$\displaystyle\bf\\\\\frac{3}{5x} =\frac{3\cdot3x^{3} }{5x\cdot 3x^{3} } =\frac{9x^{3} }{15x^{4} } \\\\\\2)\\\\\frac{6-x}{x+6} =\frac{(6-x)\cdot(x-6)}{(x+6)\cdot(x-6)}=-\frac{(x-6)(x-6)}{x^{2} -6^{2} } =\frac{(x-6)^{2} }{x^{2} -36}$