Question

Знайдіть найбільший цілий розв’язок системи нерівностей

Answer 1

$\displaystyle\bf\\\left \{ {{\dfrac{1-4x}{4}-\dfrac{x}{3}\geq \dfrac{8-x}{6}-2} \atop {\dfrac{2-3x}{3} +\dfrac{x}{5} \leq \dfrac{3+x}{15} +1}} \right. \\\\\\\left \{ {{\dfrac{1-4x}{4}\cdot 12-\dfrac{x}{3}\cdot 12\geq \dfrac{8-x}{6}\cdot 12-2\cdot 12} \atop {\dfrac{2-3x}{3} \cdot 15+\dfrac{x}{5} \cdot 15\leq \dfrac{3+x}{15} \cdot 15+1\cdot 15}} \right.\\\\\\\left \{ {{(1-4x)\cdot 3-4x\geq (8-x)\cdot 2-24} \atop {(2-3x)\cdot 5+3x\leq 3+x+15}} \right.$

$\displaystyle\bf\\\left \{ {{3-12x-4x\geq 16-2x-24} \atop {10-15x+3x\leq 18+x}} \right. \\\\\\\left \{ {{-16x+2x\geq -8-3} \atop {-12x-x\leq 18-10}} \right. \\\\\\\left \{ {{-14x\geq -11} \atop {-13x\leq 8}} \right. \\\\\\\left \{ {{x\leq \dfrac{11}{14 } \atop {x\geq -\dfrac{8}{13} }} \right. \\\\\\x\in \ \Big[-\frac{8}{13} \ ; \ \frac{11}{14} \Big]\\\\\\Otvet \ : \ 0$