Question

ПОМОГИТЕ ПОЖАЛУЙСТА! дам 50 баллов!!​

Answer 1

Ответ:

удачки!!

#2

$1)(b + 6)(b - 6) = {b}^{2} - 36 \\ 2)(2 - x)(2 + x) = 4 - {x \\ }^{2} \\ 3)(k - y)(k + y) = {k}^{2} - {y}^{2} \\ 4)(2c - 1)(2c + 1) = 4 {c}^{2} - 1 \\ 5)(7p + 3)(7p - 3) = 49 {p}^{2} - 9 \\ 6)(3 - \frac{1}{5} a)(3 + \frac{1}{5} a) = 9 - \frac{1}{25} {a }^{2} \\ 7)(5x + y)(y - 5x) = - (y + 5x)(y - 5x) = - ( {y}^{2} - 25 {x}^{2} ) = - {y}^{2} + 25 {x}^{2} \\ 8)(3c - 2k {}^{2} )(3c + 2 {k}^{2} ) = 9 {c}^{2} - 4 {k}^{4}$

#3

$1) {m}^{2} - {n}^{2} = (m - n)(m + n) \\ 2){x}^{2} - 100 = (x - 10)(x + 10) \\ 3)1 - 9 {a}^{2} = (1 - 3a)(1 + 3a) \\ 4)25 - 16 {c}^{2} = (5 - 4c)(5 + 4c) \\ 5) \frac{1}{49} - {c}^{2} = ( \frac{1}{7} - c)( \frac{1}{7} + c) \\ 6)0.09 {m}^{2} - 64 {n}^{2} = (0.3m - 8n)(0.3m + 8n) \\ 7) - \frac{36}{81} {a}^{2} + 9 {x}^{2} = - ( 3x - \frac{6}{9} {a}^{} )(3x + \frac{6}{9} a )\\ 8) {x}^{2} {y}^{2} -4 {z}^{2} = (xy - 2z)(xy + 2z)$