Question

(p-8)² = (6p - 5q)(6p +5q) = (7y - 1)² = (6p +5q)² = 2- (5n-p) ²= p²-64 = (5n+p)(5n-p) X²-1= = (2x³ - y²)(2x³ +y²) = ​

Answer 1

Ответ:

Объяснение:

(p - 8)² = p² - 2 · 8p + 8² = p² - 16p + 64

(6p - 5q)(6p + 5q) = (6p)² - (5q)² = 36p² - 25q²

(7y - 1)² = (7y)² - 2 · 7y · 1 + 1² = 49y² - 14y + 1

(6p + 5q)² = (6p)² + 2 · 6p · 5q + (5q)² = 36p² + 60pq + 25q²

2 - (5n - p)² = 2 - ((5n)² - 2 · 5np + p²) = 2 - 25n² + 10np - p²

p² - 64 = p² - 8² = (p - 8)(p + 8)

(5n + p)(5n - p) = (5n)² - p² = 25n² - p²

x² - 1 = x² - 1² = (x - 1)(x + 1)

(2x³ - y²)(2x³ + y²) = (2x³)² - (y²)² = 4x⁶ - y⁴

Использованные формулы:

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a - b)(a + b)

(a - b)(a + b) = a² - b²