Question

Найдите значения функции
пожалуйста помогите даю 60 баллов ​

Answer 1

1)

$y = \frac{1}{4} \times {( \frac{1}{2}) }^{2} + \frac{47}{8} \times \frac{1}{2} - 4 = \frac{1}{4} \times \frac{1}{4} + \frac{47}{8} \times \frac{1}{2} - 4 = \frac{1}{16} + \frac{47}{16} - 4 = \frac{48}{16} - 4 = 3 - 4 = - 1$

2)

$y = 18 \times {( - \frac{1}{3}) }^{2} + 3 \times ( - \frac{1}{3} ) - 2 = 18 \times \frac{1}{9} - 1 - 2 = 2 - 3 = - 1$

3)

$y = - {( \frac{1}{5} )}^{2} - 4 \frac{4}{5} \times \frac{1}{5} = - \frac{1}{25} - \frac{24}{5} \times \frac{1}{5} = - \frac{1}{25} - \frac{24}{25} = - \frac{25}{25} = - 1$

Answer 2

1) y = -1

$y = \frac{1}{4} {x}^{2} + \frac{47}{8} x - 4 \\ y = \frac{1}{4} \times { (\frac{1}{2} )}^{2} + \frac{47}{8} \times \frac{1}{2} - 4 \\ y = \frac{1}{16} + \frac{47}{16} - 4 \\ y = \frac{48}{16} - 4 = 3 - 4 \\ y = - 1$

2) y = -1

$y = 18 {x}^{2} + 3x - 2 \\ y = 18 \times {( - \frac{1}{3} )}^{2} + 3 \times ( - \frac{1}{3} ) - 2 \\ y = 2 - 1 - 2 \\ y = - 1$

3) y = -1

$y = - {x}^{2} - 4 \frac{4}{5} x \\ y = - ( { \frac{1}{5}) }^{2} - \frac{24}{5} \times \frac{1}{5} \\ y = - \frac{1}{25} - \frac{24}{25} = - \frac{25}{25} \\ y = - 1$