Question

1-(sin30°+cos60°)²=x
найти х :)​

Answer 1

$1 - ( \sin(30) + \cos(60) ) {}^{2} = x \\ x = 1 - ( \frac{1}{2} + \frac{1}{2} ) {}^{2} \\ x = 1 - 1 {}^{2} \\ x = 1 - 1 \\ x = 0$