Question

1252. 1) -2x-0,8y-1=0, -2x+0,2y=0;
помогите​

Answer 1

Ответ:

$2x + 0.8y = 1 \\ + \\ - 2x + 0.2y = 0 \\ 2x - 2x + 0.8y +0 .2y = 1 \\ y = 1 \\ \\ 2x + 0.8 = 1 \\ 2x = 0.2 \\ x = 0.1$

$4x - \frac{2}{3} y = - 3 \frac{2}{3} \\ - \\ 4x + 3 \frac{1}{3} y = \frac{1}{3} \\ 4x - 4x - \frac{2}{3} y - 3 \frac{1}{3} y = - 3 \frac{2}{3} - \frac{1}{3} \\ 4y = 4 \\ y = 1 \\ \\ 4x - \frac{2}{3} = - 3 \frac{2}{3} \\ 4x = - 3 \\ x = - 0.75$