Question

Допоможіть будь ласка ​

Answer 1

1) В

$y = \cos(x) \\ y' = - \sin(x) \\ x_{o} = \pi \\ y'(\pi) = - \sin(\pi) = 0$

2) А

$y = \tg(x) \\ y' = \frac{1}{ \cos {}^{2} (x) } \\ x _{o} = \pi \\ y' (\pi)= \frac{1}{ \cos {}^{2} (\pi) } = \frac{1}{( - 1) {}^{2} } = 1$

3) Г

$y = \sin(x) \\ y' = \cos(x) \\ x_{o} = \pi \\ y'(\pi) = \cos(\pi) = - 1$