Question

даю 60 балов!! срочно​

Answer 1

$\displaystyle\bf\\\Big(\sqrt{x+2\sqrt{2x-4} } -\sqrt{x-2\sqrt{2x-4} } \Big)^{2} =\\\\\\=x+2\sqrt{2x-4} -2\cdot\sqrt{(x+2\sqrt{2x-4)}\cdot(x-2\sqrt{2x-4)} } } +x-2\sqrt{2x-4} =\\\\\\=2x-2\cdot\sqrt{x^{2} -4(2x-4)} =2x-2\cdot\sqrt{x^{2} -8x+16}=\\\\\\=2x-2\cdot\sqrt{(x-4)^{2} } =2x-2\cdot(x-4)=2x-2x+8=8\\\\\\\sqrt{x+2\sqrt{2x-4} } -\sqrt{x-2\sqrt{2x-4} } =\sqrt{8} =2\sqrt{2} \\\\\\Otvet \ : \ 2\sqrt{2}$