Question

Алгебра. Даю 13 балів.

Виконати 1 завдання.

Answer 1

Ответ:

Правило :

если   $\bf |\, x\, |\leq a$  ,   то   $\bf -a\leq x\leq a$  .

$\bf |x-1|\leq 2x+1\ \ \ \Rightarrow \ \ \ -(2x+1)\leq x-1\leq 2x+1\ \ ,\\\\\left\{\begin{array}{l}\bf x-1\leq 2x+1\\\bf x-1\geq -2x-1\end{array}\right\ \ \left\{\begin{array}{l}\bf x-2x\leq 1+1\\\bf x+2x\geq 1-1\end{array}\right\ \ \left\{\begin{array}{l}\bf -x\leq 2\\\bf 3x\geq 0\end{array}\right\ \ \left\{\begin{array}{l}\bf x\geq -2\\\bf x\geq 0\end{array}\right\ \ \Rightarrow \\\\\\x\geq 0\\\\Otvet:\ \ \boldsymbol{x\in [\ 0\ ;+\infty \, )\ .}$