Question

обчислити
3 cos180°+5ctg 270°-2 sin 360°- tg² 60°​

Answer 1

cos180°= -1

ctg270°= 0

sin360°= 0

tg²60°= 0

3×(-1)+5×0-0-3= -6

Answer 2

$\displaystyle\bf\\3Cos180^\circ+5Ctg270^\circ-2Sin360^\circ-tg^{2} 60^\circ=\\\\\\=3\cdot (-1)+5\cdot 0-2\cdot 0-(\sqrt{3} )^{2} =-3+0-0-3=-6$