Question

Алгебра 8-й класс
Решите уравнение стандартным способом.

Answer 1

Ответ:

$\frac{2}{5} y + \frac{3}{10} y - \frac{2}{15} y = \frac{1}{6} \\ y(\frac{12}{30} + \frac{9}{30} - \frac{4}{30} ) = \frac{5}{30} \\ \frac{17y}{30} = \frac{5}{30} \\ 17y = 5 \\ y = \frac{5}{17}$

Answer 2

$\displaystyle\bf\\\frac{2}{5} y+\frac{3}{10} y-\frac{2}{15} y=\frac{1}{6} \\\\\\\frac{2}{5} y\cdot 30+\frac{3}{10} y\cdot 30-\frac{2}{15} y\cdot 30=\frac{1}{6}\cdot 30\\\\\\2y\cdot 6+3y\cdot 3-2y\cdot 2=5\\\\\\12y+9y-4y=5\\\\\\17y=5\\\\\\\boxed{y=\frac{5}{17} }$