Question

Помогите сделать (1;3;8) даю 20 баллов

Answer 1

$1)2\frac{1}{3} *9-1\frac{1}{3} *3\frac{1}{4} -2\frac{2}{7} *3\frac{5}{24} =\frac{7}{3} *9-\frac{4}{3} *\frac{13}{4} -\frac{16}{7} *\frac{77}{24} =7*3-\frac{13}{3} -\frac{22}{3} =\\\\=21-\frac{35}{3} =\frac{63}{3} -\frac{35}{3} =\frac{28}{3} =9\frac{1}{3}$

$3)(2\frac{1}{4} +4\frac{5}{6} ):3\frac{2}{5} -\frac{3}{4} :\frac{3}{5} =(\frac{9}{4} +\frac{29}{6} ):\frac{17}{5} -\frac{3}{4} *\frac{5}{3} =(\frac{27}{12} +\frac{58}{12} )*\frac{5}{17} -\frac{5}{4} =\frac{85}{12} *\frac{5}{17} -\frac{5}{4} =\\\\=\frac{25}{12} -\frac{5}{4} =\frac{25}{12} -\frac{15}{12} =\frac{10}{12} =\frac{5}{6}$

$8)(\frac{7}{16} -\frac{31}{40} ):(-\frac{17}{24} +\frac{27}{40} )=(\frac{35}{80} -\frac{62}{80} ):(-\frac{85}{120} +\frac{81}{120} )=-\frac{27}{80} :(-\frac{4}{120} )=\\\\=-\frac{27}{80} *(-\frac{120}{4} )=\frac{81}{8} =10\frac{1}{8}$