Question

se clai
Ca SO₂.2H₂O
———————
W (CaSO₂)-:
W (H₂O)?

Answer 1

Ответ:It seems like you're trying to balance a chemical equation involving calcium sulfate (CaSO₄·2H₂O). To balance this equation, you need to ensure that the same number of each type of atom appears on both sides of the equation.

The unbalanced equation you provided is:

CaSO₄·2H₂O → W (CaSO₄) + W (H₂O)

To balance it, let's count the atoms on each side:

On the left side:

Calcium (Ca): 1

Sulfur (S): 1

Oxygen (O): 9 (from calcium sulfate and water)

Hydrogen (H): 4 (from water)

On the right side, we have W (CaSO₄) and W (H₂O), so we don't know the exact numbers yet.

Now let's balance it step by step:

Balance the calcium (Ca) atoms:

CaSO₄·2H₂O → CaSO₄ + W (H₂O)

Balance the sulfur (S) atoms:

CaSO₄·2H₂O → CaSO₄ + W (H₂O)

Balance the oxygen (O) atoms:

On the left side: 9 (from CaSO₄·2H₂O)

On the right side: 4 (from water) + W (from CaSO₄)

To balance the oxygen atoms, we need 9 on the right side as well. So, W (from CaSO₄) = 9 - 4 = 5.

Now we have:

CaSO₄·2H₂O → CaSO₄ + 5H₂O

Balance the hydrogen (H) atoms:

On the left side: 4 (from water)

On the right side: 5 (from 5H₂O)

The hydrogen atoms are already balanced.

Now the equation is balanced:

CaSO₄·2H₂O → CaSO₄ + 5H₂O

This balanced equation represents the decomposition of calcium sulfate dihydrate (CaSO₄·2H₂O) into calcium sulfate (CaSO₄) and water (H₂O).

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