Question

(3х⁴)²=
3ау⁶×4а¹⁰ у b²=
(2x²)³×(-3xy⁵)²=
2/5a²b²³)⁰=
(1 1/2e³)³×(e⁴)⁷=
(5x³)³=
21ay⁶×4a⁷ 7²=
12a²×(-3a)⁴=
(5x³)³×(6xy⁴)²=
(2/5b²)⁰=
(-2 1/2e⁷)³×(e⁹)⁷=
(5x⁷)²=
8ay²×9a¹²y b³=
7a³×(2a)⁸=
(4x²)⁴×(-5xy³)²=
(2/5a²b¹²)⁰=
(-4 1/2e³)⁵ ×(e⁴)⁶=
СРОЧНО ДАМ 80 БАЛЛОВ!!​

Answer 1

Объяснение:

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