Question

памагите пажалуста немагу решить

Answer 1

Ответ:

1. 3 первое
2. ${x}^{ \\ 30}$
3. второе
4. ${x}^{36}$

Объяснение:

первое

$( {x}^{17} )^{2} \div {x}^{4}$

${x}^{34} \div {x}^{4}$

второе

$( {x}^{12} )^{3}$

Answer 2

Ответ:

1) Розкриемо дужки та приведемо подiбнi:

l

$8(x + 8) + 36 - 8x = \\ = 100$

$8x + 64 + 36 - 8x = \\ = 100$

$100 = 100$

Тотожнiсть доведена

2)

а) 81

б) -49

в) 97

3)

а) x^30

б) x^36

4)

а)

$- 15x {}^{6} y {}^{15}$

б)

$- 343a {}^{9} b {}^{24}$

в)

$121x {}^{4} y {}^{6}$

г)

$- 28x {}^{5} y {}^{17}$

д)

$- 180c {}^{9} p {}^{9} d {}^{12}$

е)

$864c {}^{10} d {}^{10} x {}^{7}$

Объяснение:

2)

а)

$4 {}^{3 } + 5 {}^{2} + ( - 2 {}^{3} ) = \\ = 64 + 25 - 8 = 81$

б)

$7 {}^{2} \times ( - 1) {}^{33} + 0 {}^{209} = \\ = 49 \times ( - 1) + 0 = \\ = - 49$

в)

$6 {}^{2} + 5 {}^{3} - 4 {}^{3} = \\ = 36 + 125 - 64 = \\ = 97$

3)

а)

$(x {}^{13} \times x {}^{2} \times x {}^{2} ) {}^{2} \div x {}^{4} = \\ = (x {}^{13 + 2 + 2} ) {}^{2} \div x {}^{4} = \\ = (x {}^{17} ) {}^{2} \div x {}^{4} = \\ = x {}^{34} \div x {}^{4} = \\ = x {}^{34 - 4} = \\ = x {}^{30}$

б)

$(x {}^{28} \div x {}^{19} \times x {}^{3} ) {}^{3} = \\ = (x {}^{28 - 19 + 3} ) {}^{3 } = \\ = (x {}^{12} ) {}^{3} = \\ = x {}^{12 \times 3} = \\ = x {}^{36}$

4)

а)

$- 3x {}^{3} y {}^{5} \times 5x {}^{3} y {}^{8} = \\ = - 3 \times 5 \times x {}^{3 + 3} \times y {}^{5 + 8} = \\ = - 15x {}^{6} y {}^{15}$

б)

$( - 7a {}^{3} b {}^{8} ) {}^{3} = \\ = ( - 7) {}^{3} \times a {}^{3 \times 3} \times b {}^{8 \times 3} = \\ = - 343a {}^{9} b {}^{24}$

в)

$( - 11x {}^{2} y {}^{3} ) {}^{2} = \\ = ( - 11) {}^{2} \times x {}^{2 \times 2} \times y {}^{3 \times 2} = \\ = 121x {}^{4} y {}^{6}$

г)

$7x {}^{3} y {}^{8} \times ( - 4x {}^{2} y {}^{9} ) = \\ = 7 \times ( - 4) \times x {}^{3 + 2} \times y {}^{8 + 9} = \\ = - 28x {}^{5} y {}^{17}$

д)

$18c {}^{3} p {}^{3} d {}^{9} \times ( - 2c {}^{6} p {}^{6} d {}^{3} ) \times \\ \times 5 = \\ = 18 \times ( - 2) \times 5 \times c {}^{3 + 6} \times p {}^{3 + 6} \times d {}^{9 + 3} = \\ = - 180c {}^{9} p {}^{9} d {}^{12}$

е)

$(12c {}^{4} d {}^{4} x) {}^{2} \times 6c {}^{2} d {}^{2} x {}^{5} = \\ = 12 {}^{2} \times c {}^{4 \times 2} \times d {}^{4 \times 2} \times x {}^{2} \times 6c {}^{2} \times d {}^{2} \times x {}^{5} = \\ = 864c {}^{10} d {}^{10} x {}^{7}$