Question

16 - 24x <= 8(x - 2) + 32; (7x - 5)/3 - 4 >= (9x - 3)/4
Срочно прошу!!!!!!!!!

Answer 1

Решение \(-24x+16\le 8x+16;\frac{7x-17}{3}\ge \frac{9x-3}{4}\)