Question

Как решаются данные задачи?)

Answer 1

$log_a (a^3b^6)=log_a a^3 + log_a b^6=3log_a a + 6log_a b=3cdot1+6frac{1}{log_b a}$$=3 frac{6}{log_b a}=</var>42$</p> <p> </p> <p><img src=[/tex]log_a frac{a}{b^5}=log_a a - log_a b^5=1 - 5log_a b=36" title="=3+frac{6}{log_b a}=42" title="log_a frac{a}{b^5}=log_a a - log_a b^5=1 - 5log_a b=36" title="=3+frac{6}{log_b a}=42" alt="log_a frac{a}{b^5}=log_a a - log_a b^5=1 - 5log_a b=36" title="=3+frac{6}{log_b a}=42" />

 

$=3+frac{6}{log_b a}=</var>42$

 

$<var>log_a frac{a}{b^5}=log_a a - log_a b^5=1 - 5log_a b=36" /></var></p> <p> </p> <p>[tex]frac{log_6 180}{2+log_6 5} = frac{log_6 180}{2log_6 6+log_6 5}= frac{log_6 180}{log_6 6^2+log_6 5}= frac{log_6 180}{log_6 36+log_6 5}=$$frac{log_6 180}{log_6 (36cdot5)}=frac{log_6 180}{log_6 180}=1$