Question

найдите корни уравнения 2x^2+11x+34=(x+6)^2

Answer 1

2x^2+11x+34=(x+6)^2
 2x^2+11x+34=x^2+12x+36 
2x^2+11x+34-x^2-12x-36=0
x^2-x-2=0 
D = b2 - 4ac
D = 1 + 8 = 9 = 3^2x1,2 = -b ± √D/2a
x1 = 1 + 3/2 = 4/2 = 2
x2 = 1 - 3/2= - 2/2 = -1
Ответ: x1 = 2; x2 = -1