Question

решите уравнение плииз

Answer 1

$1) x^3 + 4x^2 = 9x + 36 \ x^3 + 4x^2 - 9x -36 = 0 \ x(x^2 + 4x - 9 - 36) = 0 \ x_1 = 0 \ x^2 + 4x -9-36 = 0 \ x^2 + 4x - 45 = 0 \ D = 4^2 - 4 * (-45) = 16 + 180 = 196 \ x_2,_3 = frac{-4б sqrt{D} }{2} = frac{-4б sqrt{196} }{2} = frac{-4б 14 }{2} \ x_2 = 5\x_3 = -9$
Ответ: $-9;0;5$

$2) x^3 = x^2 + 6x\x^2 + 6x - x^3 = 0\ x(x + 6 - x^2) = 0\ x_1 = 0\ x + 6 - x^2 = 0\ x^2 - x - 6 = 0\D = (-1)^2 - 4 * (-6) = 1 + 24 = 25\ x_2,_3 = frac{1 б sqrt{D} }{2} = frac{1 б sqrt{25} }{2} = frac{1 б 5 }{2} \ x_2 = 3\x_3= - 2$
Ответ: $-2;0;3$

Answer 2

спасибо