Question

$x^{2} -x+9=(x+2) x^2$

Answer 1

$x^2 - x + 9= (x+2)x^2 \ x^2 - x + 9 = x^3 + 2x^2 \ x^2 - x + 9 - x^3 - 2x^2 = 0 \ -x^3 -x^2 - x + 9 = 0 \ x^3 +x^2 + x - 9 = 0 \ x(x^2 +x + 1 - 9) = 0 \ x_1 = 0 \ x^2 + x - 8 = 0 \ D = 1^2 - 4 * (-8) = 1 + 24 = 25 \ x_2_,_3 = frac{-1б sqrt{D} }{2} = frac{-1б sqrt{25} }{2}=frac{-1б 5 }{2} \ x_2 = 2 \ x_3 = -3$
Ответ: $-3; 0;2$