Question

$log_{2} 128*log _{6} 36$

Answer 1

$log_{2}128*iog_{6}36=log_{2}2^{7}*log_{6}6^{2}=7*2=14$

Answer 2

log_2 128 * log_6 36=log_2 2^7 * log_6 6^2=7*2=14