Question

решить уравнения (32)^x=16

упростить выражения (у^2 -4) * 3/(y-2)^2 

Answer 1

2^(5x)=2^4

5x=4

x=4/5

 

(y^2-4)*(3/(y-2)^2=(y-2)(y+2)*3/(y-2)^2=3*(y+2)/(y-2)=(3y+6)/(y-2)

Answer 2

(32)^x=16

(2^5)^x = 2^4

5x = 4

x = 0,8

(у^2 -4) * 3/(y-2)^2 = 3(y-2)(y+2)/(y-2)^2 = 3(y+2)/(y-2)