Question

log12(x + 3) + log12(x + 2) = 1
помогите решить

Answer 1

log12(x+3)+log(x+2)=log12 12
x+3+x+2=12
2x=7
x=3,5

Answer 2

ОДЗ:х>3
лог12(х+3)+лог12(х+2)=лог12(12)
x²+5x+6=12
x²+5x-6=0
x=-6
x=1
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x∉Ф